436. Find Right Interval Medium

@problem@discussion
#Array#Binary Search#Sorting



1/**
2 * [436] Find Right Interval
3 *
4 * You are given an array of intervals, where intervals[i] = [starti, endi] and each starti is unique.
5 * The right interval for an interval i is an interval j such that startj >= endi and startj is minimized. Note that i may equal j.
6 * Return an array of right interval indices for each interval i. If no right interval exists for interval i, then put -1 at index i.
7 *  
8 * Example 1:
9 * 
10 * Input: intervals = [[1,2]]
11 * Output: [-1]
12 * Explanation: There is only one interval in the collection, so it outputs -1.
13 * 
14 * Example 2:
15 * 
16 * Input: intervals = [[3,4],[2,3],[1,2]]
17 * Output: [-1,0,1]
18 * Explanation: There is no right interval for [3,4].
19 * The right interval for [2,3] is [3,4] since start0 = 3 is the smallest start that is >= end1 = 3.
20 * The right interval for [1,2] is [2,3] since start1 = 2 is the smallest start that is >= end2 = 2.
21 * 
22 * Example 3:
23 * 
24 * Input: intervals = [[1,4],[2,3],[3,4]]
25 * Output: [-1,2,-1]
26 * Explanation: There is no right interval for [1,4] and [3,4].
27 * The right interval for [2,3] is [3,4] since start2 = 3 is the smallest start that is >= end1 = 3.
28 * 
29 *  
30 * Constraints:
31 * 
32 * 	1 <= intervals.length <= 2 * 10^4
33 * 	intervals[i].length == 2
34 * 	-10^6 <= starti <= endi <= 10^6
35 * 	The start point of each interval is unique.
36 * 
37 */
38pub struct Solution {}
39
40// problem: https://leetcode.com/problems/find-right-interval/
41// discuss: https://leetcode.com/problems/find-right-interval/discuss/?currentPage=1&orderBy=most_votes&query=
42
43// submission codes start here
44
45impl Solution {
46    pub fn find_right_interval(intervals: Vec<Vec<i32>>) -> Vec<i32> {
47        vec![]
48    }
49}
50
51// submission codes end
52
53#[cfg(test)]
54mod tests {
55    use super::*;
56
57    #[test]
58    fn test_436() {
59    }
60}
61


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