2578. Split With Minimum Sum Easy
1/**
2 * [2578] Split With Minimum Sum
3 *
4 * Given a positive integer num, split it into two non-negative integers num1 and num2 such that:
5 *
6 * The concatenation of num1 and num2 is a permutation of num.
7 *
8 * In other words, the sum of the number of occurrences of each digit in num1 and num2 is equal to the number of occurrences of that digit in num.
9 *
10 *
11 * num1 and num2 can contain leading zeros.
12 *
13 * Return the minimum possible sum of num1 and num2.
14 * Notes:
15 *
16 * It is guaranteed that num does not contain any leading zeros.
17 * The order of occurrence of the digits in num1 and num2 may differ from the order of occurrence of num.
18 *
19 *
20 * <strong class="example">Example 1:
21 *
22 * Input: num = 4325
23 * Output: 59
24 * Explanation: We can split 4325 so that num1 is 24 and num2 is 35, giving a sum of 59. We can prove that 59 is indeed the minimal possible sum.
25 *
26 * <strong class="example">Example 2:
27 *
28 * Input: num = 687
29 * Output: 75
30 * Explanation: We can split 687 so that num1 is 68 and num2 is 7, which would give an optimal sum of 75.
31 *
32 *
33 * Constraints:
34 *
35 * 10 <= num <= 10^9
36 *
37 */
38pub struct Solution {}
39
40// problem: https://leetcode.com/problems/split-with-minimum-sum/
41// discuss: https://leetcode.com/problems/split-with-minimum-sum/discuss/?currentPage=1&orderBy=most_votes&query=
42
43// submission codes start here
44
45impl Solution {
46 pub fn split_num(num: i32) -> i32 {
47 0
48 }
49}
50
51// submission codes end
52
53#[cfg(test)]
54mod tests {
55 use super::*;
56
57 #[test]
58 fn test_2578() {
59 }
60}
61
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