1784. Check if Binary String Has at Most One Segment of Ones Easy

@problem@discussion
#String



1/**
2 * [1784] Check if Binary String Has at Most One Segment of Ones
3 *
4 * Given a binary string s ​​​​​without leading zeros, return true​​​ if s contains at most one contiguous segment of ones. Otherwise, return false.
5 *  
6 * Example 1:
7 * 
8 * Input: s = "1001"
9 * Output: false
10 * Explanation: The ones do not form a contiguous segment.
11 * 
12 * Example 2:
13 * 
14 * Input: s = "110"
15 * Output: true
16 *  
17 * Constraints:
18 * 
19 * 	1 <= s.length <= 100
20 * 	s[i]​​​​ is either '0' or '1'.
21 * 	s[0] is '1'.
22 * 
23 */
24pub struct Solution {}
25
26// problem: https://leetcode.com/problems/check-if-binary-string-has-at-most-one-segment-of-ones/
27// discuss: https://leetcode.com/problems/check-if-binary-string-has-at-most-one-segment-of-ones/discuss/?currentPage=1&orderBy=most_votes&query=
28
29// submission codes start here
30
31impl Solution {
32    pub fn check_ones_segment(s: String) -> bool {
33        false
34    }
35}
36
37// submission codes end
38
39#[cfg(test)]
40mod tests {
41    use super::*;
42
43    #[test]
44    fn test_1784() {
45    }
46}
47


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