1295. Find Numbers with Even Number of Digits Easy

1/**
2 * [1295] Find Numbers with Even Number of Digits
3 *
4 * Given an array nums of integers, return how many of them contain an even number of digits.
5 *  
6 * Example 1:
7 * 
8 * Input: nums = [12,345,2,6,7896]
9 * Output: 2
10 * Explanation: 
11 * 12 contains 2 digits (even number of digits). 
12 * 345 contains 3 digits (odd number of digits). 
13 * 2 contains 1 digit (odd number of digits). 
14 * 6 contains 1 digit (odd number of digits). 
15 * 7896 contains 4 digits (even number of digits). 
16 * Therefore only 12 and 7896 contain an even number of digits.
17 * 
18 * Example 2:
19 * 
20 * Input: nums = [555,901,482,1771]
21 * Output: 1 
22 * Explanation: 
23 * Only 1771 contains an even number of digits.
24 * 
25 *  
26 * Constraints:
27 * 
28 * 	1 <= nums.length <= 500
29 * 	1 <= nums[i] <= 10^5
30 * 
31 */
32pub struct Solution {}
33
34// problem: https://leetcode.com/problems/find-numbers-with-even-number-of-digits/
35// discuss: https://leetcode.com/problems/find-numbers-with-even-number-of-digits/discuss/?currentPage=1&orderBy=most_votes&query=
36
37// submission codes start here
38
39impl Solution {
40    pub fn find_numbers(nums: Vec<i32>) -> i32 {
41        0
42    }
43}
44
45// submission codes end
46
47#[cfg(test)]
48mod tests {
49    use super::*;
50
51    #[test]
52    fn test_1295() {
53    }
54}
55