121. Best Time to Buy and Sell Stock Easy

@problem@discussion
#Array#Dynamic Programming



1/**
2 * [121] Best Time to Buy and Sell Stock
3 *
4 * You are given an array prices where prices[i] is the price of a given stock on the i^th day.
5 * You want to maximize your profit by choosing a single day to buy one stock and choosing a different day in the future to sell that stock.
6 * Return the maximum profit you can achieve from this transaction. If you cannot achieve any profit, return 0.
7 *  
8 * Example 1:
9 *
10 * Input: prices = [7,1,5,3,6,4]
11 * Output: 5
12 * Explanation: Buy on day 2 (price = 1) and sell on day 5 (price = 6), profit = 6-1 = 5.
13 * Note that buying on day 2 and selling on day 1 is not allowed because you must buy before you sell.
14 *
15 * Example 2:
16 *
17 * Input: prices = [7,6,4,3,1]
18 * Output: 0
19 * Explanation: In this case, no transactions are done and the max profit = 0.
20 *
21 *  
22 * Constraints:
23 *
24 * 1 <= prices.length <= 10^5
25 * 0 <= prices[i] <= 10^4
26 *
27 */
28pub struct Solution {}
29
30// problem: https://leetcode.com/problems/best-time-to-buy-and-sell-stock/
31// discuss: https://leetcode.com/problems/best-time-to-buy-and-sell-stock/discuss/?currentPage=1&orderBy=most_votes&query=
32
33// submission codes start here
34use std::cmp;
35
36impl Solution {
37    pub fn max_profit(prices: Vec<i32>) -> i32 {
38        if prices.len() < 2 {
39            return 0;
40        }
41
42        let mut result = 0;
43        let mut previous_min = i32::MAX;
44
45        for p in prices {
46            previous_min = cmp::min(previous_min, p);
47            result = cmp::max(result, p - previous_min);
48        }
49
50        result
51    }
52}
53
54// submission codes end
55
56#[cfg(test)]
57mod tests {
58    use super::*;
59
60    #[test]
61    fn test_121() {
62        assert_eq!(Solution::max_profit(vec![7, 1, 5, 3, 6, 4]), 5);
63    }
64}
65


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